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信息
- 题目: 878.字母移位
- 标签: 前缀和
题解
Info
从后向前累加的前缀和
pub fn shifting_letters(s: String, shifts: Vec<i32>) -> String {
let mut s = s;
let ss = unsafe { s.as_bytes_mut() };
let mut sum = 0;
for i in (0..ss.len()).rev() {
sum = (sum + shifts[i]) % 26;
let tmp = (ss[i] - b'a') as i32 + sum;
ss[i] = (tmp % 26) as u8 + b'a';
}
s
}
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